Genetics From Genes To Genomes 6th Edition by Leland Hartwell – Test Bank

Description

Genetics From Genes To Genomes 6th Edition by Leland Hartwell – Test Bank

 Sample Questions

Instant Download With Answers

Genetics, 6e (Hartwell)

Chapter 2   Mendel’s Principles of Heredity

 

1) Why did Mendel perform reciprocal crosses?

1. A) To obtain enough plants to perform the experiments that Mendel wanted.
2. B) To test a hypothesis that stated the ovum carries all the information for progeny.
3. C) To be able to breed plants year round.
4. D) To determine whether the inheritance of a trait depends on which parent carries the trait.

 

Answer:  D

Section:  2.01

Topic:  Background – The Historical Puzzle of Inheritance

Learning Objective:  02.01.03 Explain the importance of Mendel’s inclusion of reciprocal crosses within his controlled breeding program of pea plants.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

2) What is the difference between cross- and self-fertilization?

1. A) In cross-fertilization the pollen from one plant is used to fertilize the egg of another plant.
2. B) In cross-fertilization the pollen from one plant is used to fertilize the egg from the same plant.
3. C) In self-fertilization the pollen from one plant is used to fertilize the egg from another plant.
4. D) In cross-fertilization insects are used to pollinate the plants, whereas in self-fertilization the investigator pollinates the plants.

 

Answer:  A

Section:  2.01

Topic:  Background – The Historical Puzzle of Inheritance

Learning Objective:  02.01.02 Describe how Mendel cross-fertilized and self-fertilized pea plants.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

3) What is the outcome of crossing two pure-breeding plants with antagonistic traits?

1. A) Only one of the traits will be seen in the progeny.
2. B) Both traits will be seen in the progeny.
3. C) Both traits will be seen in the progeny in a 3:1 ratio.
4. D) Only one trait will be seen and it will be the trait of the female.

 

Answer:  A

Section:  2.01

Topic:  Background – The Historical Puzzle of Inheritance

Learning Objective:  02.01.04 Predict the type of progeny produced by Mendel’s crosses between pure-breeding plants with discrete, antagonistic traits, such as purple versus white flowers.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

4) According to Mendel’s Law of Independent Assortment,

1. A) alleles of genes on different chromosomes assort randomly into different gametes.
2. B) alleles of genes assort into gametes grouped according to how they were inherited originally.
3. C) dominant alleles for one gene must assort into the same gamete as the dominant alleles for another gene.
4. D) dominant alleles for one gene must assort into the same gamete as the recessive alleles for another gene.

 

Answer:  A

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

5) An Ss × Ss mating is performed. If the phenotypic ratio of the progeny is 3 S– (– indicates that the other allele is unknown) to 1 ss, then

1. A) the S allele is dominant to the s
2. B) neither allele is dominant.
3. C) the s allele is dominant to the S
4. D) the relationship between the alleles cannot be determined.

 

Answer:  A

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.01 Explain Mendel’s law of segregation and how it predicts the 3:1 dominant-to-recessive phenotypic ratio among the F2 generation of a monohybrid cross.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

6) Which of the following probabilities is correct regarding a mating of an Ss RR individual to an individual who is Ss Rr ? (A – indicates the the second allele is either dominant or recessive.)

37. A) S– RR: 37.5%
38. B) Homozygous recessive: 10%
39. C) Heterozygous both alleles: 50%
40. D) ss R– : 15.5%

 

Answer:  A

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.05 Predict the genotypic and phenotypic ratios among progeny of complex multihybrid crosses using simple rules of probability.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

 

7)

 

What does the pattern of inheritance in this pedigree indicate about the disease allele?

1. A) The disease allele is recessive.
2. B) The disease allele is dominant.
3. C) There is no indication that the disease allele is either dominant or recessive.
4. D) The disease allele is not inherited but arises only by a new mutation in affected individuals.

 

Answer:  A

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

8) The mutations found in the CF gene that result in cystic fibrosis are recessive because

1. A) the protein produced by the normal allele is sufficient for normal cellular function.
2. B) the CF mutations always result in no protein being produced.
3. C) CF mutations result in a protein that has normal function only if normal CF protein also exists in the cell.
4. D) dominant alleles that cause a fatal disorder, such as cystic fibrosis, cannot be inherited.

 

Answer:  A

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.02.06 Cite the most common molecular explanations for dominant and recessive alleles.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

 

9) The reason that the HD allele acts as a dominant allele is that

1. A) the HD mutation results in a protein that can damage nerve cells even in the presence of the normal protein.
2. B) the normal HD allele does not normally produce a protein but the mutant HD allele does.
3. C) the mutant HD allele suppresses protein production from the normal HD
4. D) the protein produced from the mutant HD allele is nonfunctional.

 

Answer:  A

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.02 Explain why Huntington disease is inherited as a dominant allele while cystic fibrosis is caused by a recessive allele.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

10) If an individual has 10 gene pairs, how many different gametes can be formed if three of the gene pairs are homozygous and the remaining seven gene pairs are heterozygous?

1. A) 49
2. B) 100
3. C) 128
4. D) 1024
5. E) 131,072

 

Answer:  C

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.05 Predict the genotypic and phenotypic ratios among progeny of complex multihybrid crosses using simple rules of probability.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

11) In some genetically engineered corn plants, a Bt gene was added to a chromosome. The Bt gene specifies a protein called Bt that is lethal to certain flying insect pests that eat the corn plants. If the corn plant is is heterozygous for the Bt gene (one homolog has the introduced Bt gene and the other does not), what proportion of the sperm would carry the Bt gene? Is the presence of the Bt gene (a mutation) dominant or recessive to its absence (the wild type)?

1. A) all pollen; dominant
2. B) 1/2; dominant
3. C) 1/3; recessive
4. D) 1/4; dominant
5. E) 1/8; recessive

 

Answer:  B

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.01 Explain Mendel’s law of segregation and how it predicts the 3:1 dominant-to-recessive phenotypic ratio among the F2 generation of a monohybrid cross.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

12) Suppose that in plants, smooth seeds (S) is dominant to wrinkled seeds (s), and tall plants (T) is dominant to short plants (t). An F1 plant from a mating between homozygous plants that were tall/smooth and short/wrinkled was crossed to the short/wrinkled parent. What proportion of the progeny is homozygous for short and wrinkled alleles?

1. A) 1/2
2. B) 1/4
3. C) 1/8
4. D) 1/16
5. E) 0

 

Answer:  B

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

13) Sickle cell anemia is a recessive trait in humans. In a cross between a father who has sickle cell anemia and a mother who is heterozygous for the sickle cell allele, what is the probability that all of their first three children will be unaffected?

1. A) 1/4
2. B) 1/2
3. C) none
4. D) 1/8
5. E) 1/16

 

Answer:  D

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.05 Predict the genotypic and phenotypic ratios among progeny of complex multihybrid crosses using simple rules of probability.

Bloom’s:  5. Evaluate

Accessibility:  Keyboard Navigation

 

14) In a monohybrid cross AA × aa, what proportion of homozygotes is expected among the F2 offspring?

1. A) 1/4
2. B) 1/2
3. C) 3/4
4. D) All are homozygotes.
5. E) None are homozygotes.

 

Answer:  B

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.01 Explain Mendel’s law of segregation and how it predicts the 3:1 dominant-to-recessive phenotypic ratio among the F2 generation of a monohybrid cross.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

 

15) In a dihybrid cross AA bb × aa BB, what proportion of the F2 offspring is expected to be homozygous for at least one gene?

1. A) 1/4
2. B) 1/2
3. C) 3/4
4. D) All are homozygotes.
5. E) None are homozygotes.

 

Answer:  C

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

16) In the testcross Aa Bb × aa bb, what proportion of individuals are expected to be homozygous for both genes in the F1 generation?

1. A) 1/4
2. B) 1/2
3. C) 3/4
4. D) All are homozygotes.
5. E) None are homozygotes.

 

Answer:  A

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

17) Among the dihybrid crosses below, which will produce a 1:1 phenotypic ratio?

1. A) AA BB × aa bb
2. B) Aa Bb × Aa Bb
3. C) Aa Bb × aa bb
4. D) Aa BB × aa BB
5. E) AA bb × aa BB

 

Answer:  D

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

18) Assume that in guinea pigs, dark brown fur (B) is dominant to black fur (b). If you mate a homozygous black guinea pig with a heterozygous brown guinea pig, what proportion of the progeny will be black?

1. A) none
2. B) 1/4
3. C) 1/2
4. D) 3/4
5. E) all

 

Answer:  C

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.02 Distinguish between a monohybrid cross and a testcross.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

19) Assume that in guinea pigs, dark brown fur (B) is dominant to black fur (b). If you mate a black guinea pig with a homozygous brown guinea pig, what proportion of the progeny will be homozygous?

1. A) none
2. B) 1/4
3. C) 1/2
4. D) 3/4
5. E) all

 

Answer:  A

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.02 Distinguish between a monohybrid cross and a testcross.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

 

 

20) An allele that expresses its phenotype even when heterozygous with a recessive allele is termed

1. A) recessive.
2. B) recombinant.
3. C) dominant.
4. D) parental.
5. E) independent.

 

Answer:  C

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.01 Explain Mendel’s law of segregation and how it predicts the 3:1 dominant-to-recessive phenotypic ratio among the F2 generation of a monohybrid cross.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

21) The diploid cell formed by the fertilization of the egg by the sperm during sexual reproduction is a

1. A) reciprocal.
2. B) zygote.
3. C) dihybrid.
4. D) gamete.
5. E) monohybrid.

 

Answer:  B

Section:  2.01

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.01 Explain Mendel’s law of segregation and how it predicts the 3:1 dominant-to-recessive phenotypic ratio among the F2 generation of a monohybrid cross.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

22) The alleles present in an individual make up the individual’s

1. A) recombinant types.
2. B) recessiveness.
3. C) dominance.
4. D) phenotype.
5. E) genotype.

 

Answer:  E

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.02 Distinguish between a monohybrid cross and a testcross.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

 

 

23) The first offspring from the parents are called

1. A) P.
2. B) F
3. C) F
4. D) a testcross.
5. E) P

 

Answer:  B

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.01 Explain Mendel’s law of segregation and how it predicts the 3:1 dominant-to-recessive phenotypic ratio among the F2 generation of a monohybrid cross.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

24) What type of cross is performed to determine the genotype of an individual?

1. A) A testcross
2. B) A dihybrid cross
3. C) A monohybrid cross
4. D) A  genotyping cross
5. E) A controlled cross

 

Answer:  A

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.02 Distinguish between a monohybrid cross and a testcross.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

25) If the parents of a family already have two boys, what is the probability that the next two offspring will both be girls?

1. A) 1
2. B) 1/2
3. C) 1/3
4. D) 1/4
5. E) 1/8

 

Answer:  D

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.05 Predict the genotypic and phenotypic ratios among progeny of complex multihybrid crosses using simple rules of probability.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

 

26) Suppose that in plants, smooth seeds (S) is dominant to wrinkled seeds (s) and tall plants (T) is dominant to short plants (t). An F1 tall plant with smooth seeds was crossed to a parent plant that was short and wrinkled. What proportion of the progeny is expected to be heterozygous for tall and smooth?

1. A) 1/2
2. B) 1/4
3. C) 1/8
4. D) 1/16
5. E) 0

 

Answer:  B

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio among the F2 of a dihybrid cross provides evidence for this law.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

27) A rare recessive trait in a pedigree is indicated by which pattern of inheritance?

1. A) vertical
2. B) horizontal
3. C) diagonal
4. D) both vertical and horizontal
5. E) pure-breeding

 

Answer:  B

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

 

28) The dominant Huntington disease allele causes severe neural/brain damage at approximately age 40. A female whose mother has Huntington disease marries a male whose parents are normal. It is not known if the female has the disease. Keeping in mind that the disease allele is rare in the population, what is the probability that their firstborn will inherit the gene that causes Huntington disease?

1. A) 25%
2. B) 50%
3. C) 75%
4. D) 100%
5. E) 0%

 

Answer:  A

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.02 Explain why Huntington disease is inherited as a dominant allele while cystic fibrosis is caused by a recessive allele.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

29) In a monohybrid cross AA × aa, what proportion of heterozygotes is expected among the F2 offspring?

1. A) 1/4
2. B) 1/2
3. C) 3/4
4. D) All are heterozygotes.
5. E) None are heterozygotes.

 

Answer:  B

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.01 Explain Mendel’s law of segregation and how it predicts the 3:1 dominant-to-recessive phenotypic ratio among the F2 generation of a monohybrid cross.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

30) In a dihybrid cross AA BB × aa bb, what proportion of heterozygotes for both gene pairs is expected among the F2 offspring?

1. A) 1/4
2. B) 1/2
3. C) 3/4
4. D) All are heterozygotes.
5. E) None are heterozygotes.

 

Answer:  A

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

31) In the dihybrid cross Aa Bb × aa bb, what proportion of heterozygotes for both gene pairs is expected among the F1 offspring?

1. A) 1/4
2. B) 1/2
3. C) 3/4
4. D) All are heterozygotes.
5. E) None are heterozygotes.

 

Answer:  A

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

 

32) Among the dihybrid crosses below, which will produce offspring with a 1:1:1:1 genotypic ratio?

1. A) AA BB × aa bb
2. B) Aa Bb × Aa Bb
3. C) Aa Bb × aa bb
4. D) Aa BB × aa BB
5. E) AA bb × aa BB

 

Answer:  C

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.04 Interpret phenotypic ratios of progeny to infer how particular traits are inherited.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

33) What is the term for crosses between parents that differ in only one trait?

1. A) Testcrosses
2. B) Cross fertilize
3. C) Monohybrid crosses
4. D) Dihybrid crosses
5. E) Reciprocal crosses

 

Answer:  C

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.02 Distinguish between a monohybrid cross and a testcross.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

34) An alternative form of a single gene is known as

1. A) a parental.
2. B) a dihybrid.
3. C) a reciprocal.
4. D) an allele.
5. E) a recessive.

 

Answer:  D

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.01 Explain Mendel’s law of segregation and how it predicts the 3:1 dominant-to-recessive phenotypic ratio among the F2 generation of a monohybrid cross.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

 

 

35) A phenotype reflecting a new combination of genes occurring during gamete formation is called

1. A) a recombinant type.
2. B) an independent assortment.
3. C) heterozygous.
4. D) homozygous.
5. E) a multihybrid cross.

 

Answer:  A

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

For each of the following pedigree symbols, select the correct meaning.

36)

1. A) Unaffected male
2. B) Unaffected female
3. C) Mating
4. D) Affected male
5. E) Affected female

 

Answer:  A

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

 

 

37)

1. A) Unaffected male
2. B) Unaffected female
3. C) Mating
4. D) Affected male
5. E) Affected female

 

Answer:  C

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

38)

1. A) Unaffected male
2. B) Unaffected female
3. C) Mating
4. D) Affected male
5. E) Affected female

 

Answer:  B

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

 

 

39)

1. A) Unaffected male
2. B) Unaffected female
3. C) Mating
4. D) Affected male
5. E) Affected female

 

Answer:  D

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

Below is a pedigree for a common human trait (not a disease) controlled by a single gene. Shaded symbols are for individuals exhibiting the trait.

 

40) Identify the mode of inheritance of the trait.

1. A) Dominant
2. B) Recessive
3. C) Either dominant or recessive
4. D) Cannot be determined

 

Answer:  B

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

 

41) If individuals 4 and 7 have a child, what is the probability that the child will exhibit the trait?

1. A) 1/4
2. B) 1/2
3. C) 1/6
4. D) 2/3
5. E) 0

 

Answer:  C

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

Below is a pedigree of a human genetic disease in which solid color indicates affected individuals. Assume that the disease is caused by a gene that can have the alleles A or a.

 

42) Based on this pedigree, what is the most likely mode of inheritance?

1. A) Dominant
2. B) Recessive
3. C) Either dominant or recessive
4. D) Cannot be determined

 

Answer:  A

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

 

43) What is/are the possible genotype(s) of person 1?

1. A) AA
2. B) Aa
3. C) Either AA or Aa
4. D) aa
5. E) Cannot be determined

 

Answer:  D

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

44) What is/are the possible genotype(s) of person 2?

1. A) AA
2. B) Aa
3. C) Either AA or Aa
4. D) aa
5. E) Cannot be determined

 

Answer:  D

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

45) What is/are the possible genotype(s) of person 3?

1. A) AA
2. B) Aa
3. C) Either AA or Aa
4. D) aa
5. E) Cannot be determined

 

Answer:  D

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

 

46) What is/are the possible genotype(s) of person 4?

1. A) AA
2. B) Aa
3. C) Either AA or Aa
4. D) aa
5. E) Cannot be determined

 

Answer:  B

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

47) If individuals 1 and 4 have a child together, what is the probability that the child will exhibit the disease?

1. A) 0%
2. B) 25%
3. C) 50%
4. D) 75%
5. E) 100%

 

Answer:  C

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

48) If individuals 2 and 3 have a child together, what is the probability that the child will exhibit the disease?

1. A) 0%
2. B) 25%
3. C) 50%
4. D) 75%
5. E) 100%

 

Answer:  A

Section:  2.03

Topic:  Mendelian Inheritance in Humans

Learning Objective:  02.03.01 Analyze human pedigrees to determine whether a genetic disease exhibits recessive or dominant inheritance.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

In corn, having ligules (L) is dominant to liguleless (l), and green leaves (G) is dominant to white leaves (g).

 

49) If a testcross is performed with a dihybrid plant with ligules and green leaves, what proportion of the progeny would be green and liguleless?

1. A) 1/16
2. B) 1/8
3. C) 1/4
4. D) 1/2
5. E) Cannot be determined

 

Answer:  C

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

50) If a pure-breeding liguleless plant with green leaves is crossed to pure-breeding plant with ligules and white leaves, predict the proportion of F2 progeny with the genotype Ll gg.

1. A) 1/16
2. B) 1/8
3. C) 1/4
4. D) 1/2
5. E) Cannot be determined

 

Answer:  B

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

 

 

51) If a pure-breeding plant that is liguleless and has green leaves is crossed to a pure-breeding plant with white leaves and ligules, predict the genotypes and phenotypes of the F1.

1. A) LL GG, green and ligules
2. B) Ll GG, green and ligules
3. C) Ll Gg, green and ligules
4. D) ll gg, white and liguleless
5. E) Ll gg, green and liguleless

 

Answer:  C

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

52) How was the approach taken by Mendel similar to the approaches taken by modern scientific inquiry?

1. A) Mendel repeated his experiments.
2. B) Mendel examined both continuous and discrete traits.
3. C) Mendel used the same technical methods that are used today.
4. D) Mendel’s experiments challenged no hypotheses that were favored at the time.

 

Answer:  A

Section:  2.01

Topic:  Background – The Historical Puzzle of Inheritance

Learning Objective:  02.01.01 Relate how Mendel’s experimental approach is similar to the process of modern scientific inquiry.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

53) Pea shape is controlled by a gene that specifies an enzyme known as Sbe1 (for Starch-branching enzyme 1). A recessive allele of Sbe1 likely encodes

1. A) an Sbe1 enzyme with reduced function.
2. B) an Sbe1 enzyme with a new function.
3. C) a different type of enzyme.
4. D) an Sbe1 enzyme with enhanced catalytic activity.

 

Answer:  A

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.06 Cite the most common molecular explanations for dominant and recessive alleles.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

54) An allele of the pea color gene specifies the enzyme Sgr, which normally functions in a pathway to break down chlorophyll during pea maturation, resulting in yellow mature peas. A second allele of the Sgr gene produces no enzyme and is the ________ allele.

1. A) dominant
2. B) recessive
3. C) wild-type
4. D) functioning

 

Answer:  B

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.06 Cite the most common molecular explanations for dominant and recessive alleles.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

55) Mendel’s law of independent assortment dictates than an Aa Bb dihybrid would make equal numbers of four gamete types. What are these four gamete types?

1. A) A; a; B; b
2. B) AA; BB; aa; bb
3. C) A B; A b; a B; a b
4. D) AA BB; AA bb; Aa Bb; aa BB

 

Answer:  C

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

56) According to Mendel’s law of equal segregation, an Aa monohybrid makes two types of gametes with equal frequency. These two gamete types are:

1. A) AA and aa
2. B) A and a
3. C) Aa and aa
4. D) AA and Aa

 

Answer:  B

Section:  2.02

Topic:  Genetic Analysis According to Mendel

Learning Objective:  02.02.03 Explain Mendel’s law of independent assortment and how the 9:3:3:1 phenotypic ratio in a dihybrid cross provides evidence for this law.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

Genetics, 6e (Hartwell)

Chapter 4   The Chromosome Theory of Inheritance

 

1) Which types of chromosomes provide the basis for sex determination in most mammals?

1. A) haploid set of chromosomes
2. B) diploid set of chromosomes
3. C) autosomes
4. D) sex chromosomes
5. E) homologous chromosomes

 

Answer:  D

Section:  04.02

Topic:  Sex Chromosomes and Sex Determination

Learning Objective:  04.02.03 Compare the means of sex determination in different organisms.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

2) InDrosophila virilis, somatic cell nuclei contain 12 chromosomes while sperm nuclei contain only 6 chromosomes. What does n equal for this species?

1. A) 3
2. B) 6
3. C) 12
4. D) 24
5. E) 6 or 12, depending on cell type

 

Answer:  B

Section:  04.01

Topic:  Chromosomes – The Carriers of Genes

Learning Objective:  04.01.01 Differentiate among somatic cells, gametes, and zygotes with regard to the number and origin of their chromosomes.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

3) The stage of mitosis when chromosomes condense to form rod-shaped structures visible under the microscope is called

1. A) interphase.
2. B) prophase.
3. C) metaphase.
4. D) anaphase.
5. E) telophase.

 

Answer:  B

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.01 Describe the key chromosome behaviors during mitosis.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

4) The stage of mitosis when sister chromatids separate from each other and migrate to opposite poles of a cell is called

1. A) interphase.
2. B) prophase.
3. C) metaphase.
4. D) anaphase.
5. E) telophase.

 

Answer:  D

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.01 Describe the key chromosome behaviors during mitosis.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

5) During which of the following stages of the cell cycle would a chromosome consist of only a single chromatid?

1. A) G1
2. B) G2
3. C) mitotic prophase
4. D) mitotic metaphase
5. E) All of the choices are correct.

 

Answer:  A

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.01 Describe the key chromosome behaviors during mitosis.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

6) Which of the following statements applies to homologous nonsister chromatids?

1. A) Their centromeres are attached during meiosis II.
2. B) They are genetically identical.
3. C) They segregate from each other at anaphase of mitosis.
4. D) They contain the same genes in the same order but may have different alleles of some genes.
5. E) More than one statement applies to homologous chromatids.

 

Answer:  D

Section:  04.01

Topic:  Chromosomes – The Carriers of Genes

Learning Objective:  04.01.02 Distinguish between homologous and nonhomologous chromosomes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

 

7) Drosophila melanogaster has four pairs of chromosomes (including a pair of sex chromosomes). Sperm from this species are formed by a meiotic process in which homologous chromosomes pair and segregate but do not undergo crossing-over. How many genetically different kinds of sperm could be produced by a Drosophila melanogaster male (XY)?

1. A) 4
2. B) 8
3. C) 16
4. D) 64
5. E) 256

 

Answer:  C

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.03 Explain how the independent alignment of homologs, and also crossing-over during the first meiotic division, each contribute to the genetic diversity of gametes.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

8) Nondisjunction can occur at either the first or second division of meiosis. XYY individuals would most likely arise from nondisjunction at the ________ meiotic division in the ________.

1. A) first; mother
2. B) second; mother
3. C) first; father
4. D) second; father
5. E) More than one of the choices could give rise to XYY individuals.

 

Answer:  D

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.03 Predict phenotypes associated with nondisjunction of sex chromosomes.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

9) Nondisjunction can occur at either the first or second division of meiosis. XXY individuals could arise from nondisjunction at the ________ meiotic division in the ________.

1. A) first; mother
2. B) second; mother
3. C) first; father
4. D) second; father
5. E) More than one of the choices could give rise to XXY individuals.

 

Answer:  E

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.03 Predict phenotypes associated with nondisjunction of sex chromosomes.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

10) Crossing-over between homologous chromosomes occurs at which of the following stages of meiosis?

1. A) S phase
2. B) prophase I
3. C) metaphase I
4. D) anaphase I
5. E) prophase II

 

Answer:  B

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.03 Explain how the independent alignment of homologs, and also crossing-over during the first meiotic division, each contribute to the genetic diversity of gametes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

 

 

11) Humans have 22 pairs of autosomes plus one sex chromosome pair. How many autosomes are present in a normal human primary spermatocyte?

1. A) 22
2. B) 23
3. C) 44
4. D) 45
5. E) 46

 

Answer:  E

Section:  04.05

Topic:  Gametogenesis

Learning Objective:  04.05.02 Distinguish between the sex chromosome complements of human female and male germ-line cells at different stages of gametogenesis.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

12) Premeiotic germ cells that divide mitotically in females are

1. A) primary oocytes.
2. B) secondary oocytes.
3. C) ootids.
4. D) oogonia.
5. E) ova.

 

Answer:  D

Section:  04.05

Topic:  Gametogenesis

Learning Objective:  04.05.01 Compare the processes of oogenesis and spermatogenesis in humans.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

13) The cells that undergo meiosis in males are

1. A) spermatocytes.
2. B) spermatogonia.
3. C) spermatids.
4. D) oocytes.
5. E) sperm.

 

Answer:  A

Section:  04.05

Topic:  Gametogenesis

Learning Objective:  04.05.01 Compare the processes of oogenesis and spermatogenesis in humans.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

 

 

14) A chromosome with two arms of similar length is referred to as

1. A) acrocentric.
2. B) homologous.
3. C) telocentric.
4. D) metazoan.
5. E) metacentric.

 

Answer:  E

Section:  04.01

Topic:  Chromosomes – The Carriers of Genes

Learning Objective:  04.01.01 Differentiate among somatic cells, gametes, and zygotes with regard to the number and origin of their chromosomes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

15) At which of the following stages of meiosis would homologous chromosomes be paired?

1. A) prophase of meiosis I
2. B) both prophase of meiosis I and prophase of meiosis II
3. C) metaphase of meiosis I
4. D) metaphase of meiosis II
5. E) both prophase of meiosis I and metaphase of meiosis I

 

Answer:  E

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.01 Describe the key chromosome behaviors during meiosis that lead to haploid gametes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

16) Which of the following events occurs during mitosis but not during meiosis?

1. A) Sister chromatids segregate.
2. B) Homologous chromosomes pair.
3. C) Crossing-over occurs between homologous chromosomes.
4. D) Chromosomes align on the metaphase plate.
5. E) None of the choices is correct.

 

Answer:  E

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.02 Compare chromosome behaviors during mitosis and meiosis.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

 

 

17) The mitotic stage during which chromosomes begin attaching to spindle fibers and moving randomly and reversibly to the centrosomes is

1. A) prophase.
2. B) prometaphase.
3. C) metaphase.
4. D) anaphase.
5. E) telophase.

 

Answer:  B

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.02 Diagram the forces and structures that dictate chromosomal movement during mitosis.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

18) The chromosomal structure to which spindle fibers attach during the mitotic divisions is the

1. A) chromatid.
2. B) centrosome.
3. C) kinetochore.
4. D) metaphase plate.
5. E) centromere.

 

Answer:  C

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.02 Diagram the forces and structures that dictate chromosomal movement during mitosis.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

19) Microtubules that originate at opposite centrosomes and interdigitate near the cell’s equator without attaching to chromosomes are the

1. A) kinetochore microtubules.
2. B) polar microtubules.
3. C) astral microtubules.
4. D) interdigitating microtubules.

 

Answer:  B

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.02 Diagram the forces and structures that dictate chromosomal movement during mitosis.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

 

 

20) Mitosis results in ________ chromosome number, whereas meiosis results in ________ chromosome number.

1. A) a doubling of; no change in
2. B) no change in; no change in
3. C) a reduction by half in; no change in
4. D) no change in; a doubling of
5. E) no change in; a reduction by half in

 

Answer:  E

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.02 Compare chromosome behaviors during mitosis and meiosis.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

21) Cells in the G0 stage

1. A) have two chromatids per chromosome.
2. B) are replicating their chromosomes.
3. C) are about to enter the mitotic phase of the cell cycle.
4. D) are in an extended G1phase and no longer dividing.
5. E) are dead.

 

Answer:  D

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.01 Describe the key chromosome behaviors during mitosis.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

22) Cells in the G2 stage of the cell cycle have ________ as cells of the same species in the G1 stage.

1. A) twice as many crossovers
2. B) twice as many chromatids
3. C) half as many chromatids
4. D) the same number of chromatids
5. E) half as many chromosomes

 

Answer:  B

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.01 Describe the key chromosome behaviors during mitosis.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

 

 

23) Normal fruit flies have red eyes. Flies with mutations that block the function of the X-linked white gene have white eyes. The wild-type allele is completely dominant to mutant alleles. A cross between a white-eyed female fruit fly and a red-eyed male would generate which of the following types of progeny?

1. A) red-eyed females and white-eyed males
2. B) white-eyed females and red-eyed males
3. C) all red-eyed females and a 50:50 mixture of white-eyed and red-eyed males
4. D) all red-eyed males and a 50:50 mixture of white-eyed and red-eyed females
5. E) The result cannot be predicted because it depends on whether the female is homozygous or heterozygous.

 

Answer:  A

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.02 Infer from the results of crosses whether or not a trait is sex-linked.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

24) Red-green color blindness is controlled by an X-linked gene in humans. The allele that causes color blindness is recessive to the allele for normal vision. A man and woman both with normal vision had color-blind fathers. If this man and woman have a child, what is the probability that the child will be color blind?

1. A) 1/2
2. B) 1/4
3. C) 1/8
4. D) 1/3
5. E) 0

 

Answer:  B

Section:  04.07

Topic:  Sex-Linked and Sexually Dimorphic Traits in Humans

Learning Objective:  04.07.01 Determine from pedigree analysis whether human traits are X-linked or autosomal.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

 

25) Hemophilia is caused by an X-linked recessive mutation in humans. If a woman whose paternal uncle (father’s brother) was a hemophiliac marries a man whose brother is also a hemophiliac, what is the probability that their first child will have hemophilia? (Assume that no other cases of hemophilia and no hidden carriers exist in the pedigree.)

1. A) 0
2. B) 1/4
3. C) 1/2
4. D) 1/8
5. E) 1

 

Answer:  A

Section:  04.07

Topic:  Sex-Linked and Sexually Dimorphic Traits in Humans

Learning Objective:  04.07.01 Determine from pedigree analysis whether human traits are X-linked or autosomal.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

26) Normal fruit flies have red eyes. Flies with mutations that block the function of the X-linked white gene have white eyes. The wild-type allele is completely dominant to mutant alleles. A white-eyed female fruit fly is mated to a red-eyed male. One of their hundreds of female progeny is white-eyed. What is the likely karyotype of this white-eyed daughter?

1. A) XX
2. B) XXY
3. C) XO
4. D) XXX
5. E) XYY

 

Answer:  B

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.03 Predict phenotypes associated with nondisjunction of sex chromosomes.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

 

27) Normal fruit flies have red eyes. Flies with mutations that block the function of the X-linked white gene have white eyes. The wild-type allele is completely dominant to mutant alleles. A white-eyed female fruit fly is mated to a red-eyed male. One of their hundreds of female progeny is white-eyed. This white-eyed daughter likely arose from nondisjunction of the sex chromosomes during ________ in the ________.

1. A) meiosis I; mother
2. B) meiosis II; mother
3. C) meiosis I; father
4. D) meiosis II; father
5. E) meiosis I or II; mother

 

Answer:  E

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.03 Predict phenotypes associated with nondisjunction of sex chromosomes.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

28) Males with one copy of an X-linked gene are said to be ________ for that gene.

1. A) homozygous
2. B) heteroallelic
3. C) heterozygous
4. D) hemizygous
5. E) deficient

 

Answer:  D

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.01 Describe the key events of meiosis that explain Mendel’s first and second laws.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

 

 

29) In chickens, females have two different sex chromosomes (Z and W), while the males have two Z chromosomes. A Z-linked gene controls the pattern of the feathers, with the dominant B allele causing the barred pattern and the b allele causing nonbarred feathers. Which of the following crosses would produce all daughters of one type (barred or nonbarred) and all sons of the other type?

1. A) barred females × nonbarred males
2. B) nonbarred females × barred males
3. C) nonbarred females × nonbarred males
4. D) barred females × barred males
5. E) More than one of the choices is correct.

 

Answer:  A

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.02 Infer from the results of crosses whether or not a trait is sex-linked.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

30) Suppose you discover a new species of worm that exists in two forms—slimy and nonslimy. You find that mating slimy females to nonslimy males produces offspring consisting of slimy males and nonslimy females, whereas mating nonslimy females with slimy males produces offspring of both sexes that are all slimy. You would conclude that the ________ allele is dominant and that ________ are the heterogametic sex (the sex with two different sex chromosomes) in this species of worm.

1. A) slimy; females
2. B) slimy; males
3. C) nonslimy; females
4. D) nonslimy; males

 

Answer:  A

Section:  04.02

Topic:  Sex Chromosomes and Sex Determination

Learning Objective:  04.02.03 Compare the means of sex determination in different organisms.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

 

31) Which of the following is not a property of homologous chromosomes?

1. A) They pair physically during prophase of meiosis I.
2. B) They exchange genes by crossing over during meiosis.
3. C) They carry alleles for the same genes at the same chromosomal position.
4. D) Their centromeres are attached to each other during G2 of the cell cycle.
5. E) They segregate to opposite poles at anaphase of meiosis I.

 

Answer:  D

Section:  04.01

Topic:  Chromosomes – The Carriers of Genes

Learning Objective:  04.01.02 Distinguish between homologous and nonhomologous chromosomes.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

32) Suppose you discover a mouse that has spiky fur instead of the usual soft fur. You notice that this trait seems to be present only in males. To investigate this pattern, you cross a spiky-fur male with a soft-fur female, and find that all the F1 progeny of both sexes have soft fur. You then interbreed the F1 and observe that all the F2 females have soft fur, but 1/4 of the F2 males have spiky fur. You conclude that the spiky allele is

1. A) an X-linked recessive.
2. B) Y-linked.
3. C) autosomal recessive with sex-influenced expression.
4. D) an X-linked dominant.
5. E) an autosomal dominant with sex-influenced expression.

 

Answer:  C

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.02 Infer from the results of crosses whether or not a trait is sex-linked.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

 

33) In fruit flies, brown eyes can be caused by recessive mutant alleles of any one of three genes: pn (prune), bw (brown) or ry (rosy). The pn gene is X-linked, bw is on the second chromosome, and ry is on the third chromosome. One wild-type allele of each of the three genes must be present for eyes to be red (wild type). Suppose that two brown-eyed flies are crossed and their progeny consist of brown-eyed sons and red-eyed daughters. Which mutation is responsible for the brown eyes in the parental female?

1. A) pn
2. B) bw
3. C) ry
4. D) either bw or ry
5. E) any of the three—pn, bw, or ry

 

Answer:  A

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.02 Infer from the results of crosses whether or not a trait is sex-linked.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

34) Color vision depends on dominant alleles of three different genes: the R gene and the G gene, both on the X chromosome, and the B gene, which is autosomal. Recessive mutant alleles of any one of these three genes can cause color blindness in homozygotes. Suppose a color-blind man marries a color-blind woman and all their offspring have normal vision. What is the genotype of the woman?

1. A) RR GG bb
2. B) RR gg BB
3. C) rr GG bb
4. D) RR gg BB or RR GG bb
5. E) rr GG bb or rr gg BB

 

Answer:  A

Section:  04.07

Topic:  Sex-Linked and Sexually Dimorphic Traits in Humans

Learning Objective:  04.07.01 Determine from pedigree analysis whether human traits are X-linked or autosomal.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

 

35) A variable trait in corn is the presence or absence of knobs at particular sites on some chromosomes. The allele present on each chromosome determines whether or not that chromosome has a knob. Suppose that one member of each of two pairs of homologs in a corn plant has a knob. If this plant is crossed with a knobless plant, what percentage of the offspring is expected to have only knobless chromosomes?

1. A) 100%
2. B) 75%
3. C) 50%
4. D) 25%
5. E) 0%

 

Answer:  D

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.02 Infer from the results of crosses whether or not a trait is sex-linked.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

36) What aspect of chromosome behavior most clearly accounts for Mendel’s law of segregation?

1. A) movement of sister chromatids to opposite poles at anaphase II of meiosis
2. B) movement of homologous chromosomes to opposite poles at anaphase I of meiosis
3. C) crossing-over between homologous chromosomes during prophase I of meiosis
4. D) replication of chromosomes prior to meiosis
5. E) independent alignment of different homologous pairs on the metaphase I spindle

 

Answer:  B

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.01 Describe the key events of meiosis that explain Mendel’s first and second laws.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

 

 

37) What aspect of chromosome behavior most clearly accounts for Mendel’s law of independent assortment?

1. A) movement of sister chromatids to opposite poles at anaphase II of meiosis
2. B) movement of homologous chromosomes to opposite poles at anaphase I of meiosis
3. C) crossing over between homologous chromosomes during prophase I of meiosis
4. D) replication of chromosomes prior to meiosis
5. E) independent alignment of different homologous pairs on the metaphase I spindle

 

Answer:  E

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.01 Describe the key events of meiosis that explain Mendel’s first and second laws.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

38) Which aspect(s) of chromosome behavior is/are primarily responsible for the tremendous amount of genetic variability associated with sexual reproduction?

1. A) segregation of sister chromatids at anaphase II of meiosis
2. B) segregation of homologous chromosomes at anaphase I of meiosis
3. C) crossing-over between homologous chromosomes during prophase I of meiosis
4. D) independent alignment of different homologous pairs on the metaphase I spindle
5. E) both crossing-over between homologous chromosomes during prophase I of meiosis and independent alignment of different homologous pairs on the metaphase I spindle

 

Answer:  E

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.03 Explain how the independent alignment of homologs, and also crossing-over during the first meiotic division, each contribute to the genetic diversity of gametes.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

39) Which sex chromosomes are present in only one sex?

1. A) X and Z
2. B) X and W
3. C) Y and Z
4. D) Y and W
5. E) X and Y

 

Answer:  D

Section:  04.02

Topic:  Sex Chromosomes and Sex Determination

Learning Objective:  04.02.03 Compare the means of sex determination in different organisms.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

40) In the following pedigree, the indicated trait is most likely caused by which type of allele?

 

 

1. A) autosomal recessive
2. B) autosomal dominant
3. C) X-linked recessive
4. D) X-linked dominant
5. E) Y-linked

 

Answer:  C

Section:  04.07

Topic:  Sex-Linked and Sexually Dimorphic Traits in Humans

Learning Objective:  04.07.01 Determine from pedigree analysis whether human traits are X-linked or autosomal.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

41) In the following pedigree, the indicated trait most likely is caused by which type of allele?

 

 

 

1. A) autosomal recessive
2. B) autosomal dominant
3. C) X-linked recessive
4. D) X-linked dominant
5. E) Y-linked

 

Answer:  D

Section:  04.07

Topic:  Sex-Linked and Sexually Dimorphic Traits in Humans

Learning Objective:  04.07.01 Determine from pedigree analysis whether human traits are X-linked or autosomal.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

42) In the following pedigree, the indicated trait is most likely caused by which type of allele?

 

 

 

1. A) autosomal recessive
2. B) autosomal dominant
3. C) X-linked recessive
4. D) X-linked dominant
5. E) Y-linked

 

Answer:  B

Section:  04.07

Topic:  Sex-Linked and Sexually Dimorphic Traits in Humans

Learning Objective:  04.07.01 Determine from pedigree analysis whether human traits are X-linked or autosomal.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

43) In the following pedigree, the indicated trait is most likely caused by which type of allele?

 

 

1. A) autosomal recessive
2. B) autosomal dominant
3. C) X-linked recessive
4. D) X-linked dominant
5. E) Y-linked

 

Answer:  A

Section:  04.07

Topic:  Sex-Linked and Sexually Dimorphic Traits in Humans

Learning Objective:  04.07.01 Determine from pedigree analysis whether human traits are X-linked or autosomal.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

44) In the following pedigree, the indicated trait is caused by what type of allele?

 

 

 

1. A) autosomal recessive
2. B) autosomal dominant
3. C) X-linked recessive
4. D) X-linked dominant
5. E) Y-linked

 

Answer:  E

Section:  04.07

Topic:  Sex-Linked and Sexually Dimorphic Traits in Humans

Learning Objective:  04.07.01 Determine from pedigree analysis whether human traits are X-linked or autosomal.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

45) In fruit flies, an X-linked dominant mutant allele of the Notch gene (N) causes Notched wings in heterozygous females but is lethal in hemizygous or homozygous condition. What ratio of offspring would be observed in a cross of a Notched-wing female with a normal male?

1. A) 1/3 Notched-wing females, 1/3 normal females, 1/3 normal males
2. B) 1/4 Notched-wing females, 1/4 normal females, 1/4 Notched-wing males, 1/4 normal males
3. C) 1/2 Notched-wing females, 1/2 normal males
4. D) 1/2 normal females, 1/2 Notched-wing males
5. E) 2/3 Notched-wing females, 1/3 normal males

 

Answer:  A

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.02 Infer from the results of crosses whether or not a trait is sex-linked.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

46) What is the correct order of these mitotic events?

A Chromosomes align on the midplate of the cell.

B Kinetochores begin attaching to spindle fibers.

C Nuclear membrane reforms and chromosomes decondense.

D Chromosomes condense and centrosomes migrate to opposite sides of nucleus.

E Sister chromatids separate and move to opposite poles.

 

1. A) BDACE
2. B) DABEC
3. C) DBAEC
4. D) ABDCE
5. E) EDBAC

 

Answer:  C

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.01 Describe the key chromosome behaviors during mitosis.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

47) What is the correct order of these meiotic events?

A Segregation of homologous chromosomes to opposite poles.

B Segregation of sister chromatids to opposite poles.

C Alignment of homologous pairs on the midplate of the cell.

D Pairing and synapsis of homologous chromosomes.

E Condensation of chromosomes in a diploid nucleus.

 

1. A) CDEAB
2. B) DCEBA
3. C) EDCBA
4. D) EDCAB
5. E) DCABE

 

Answer:  D

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.01 Describe the key chromosome behaviors during meiosis that lead to haploid gametes.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

 

48) A diploid cell with three pairs of chromosomes has the genotype Aa Bb Cc, where each gene is on a different chromosome. If this cell were to undergo meiotic division, how many genetically different types of gametes could be produced?

1. A) 1
2. B) 3
3. C) 6
4. D) 8
5. E) 9

 

Answer:  D

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.03 Explain how the independent alignment of homologs, and also crossing-over during the first meiotic division, each contribute to the genetic diversity of gametes.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

49) A cell with three pairs of chromosomes has the genotype Aa Bb Cc, with each locus on a different chromosome. If this cell were to undergo mitotic division, how many genetically different types of daughter cells could be produced?

1. A) 1
2. B) 3
3. C) 6
4. D) 8
5. E) 9

 

Answer:  A

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.01 Describe the key chromosome behaviors during mitosis.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

 

 

50) In humans, XO individuals are females with Turner syndrome and XXY individuals are males with Klinefelter syndrome. Which of the following events cannot give rise to a Klinefelter male?

1. A) nondisjunction at meiosis I in the mother
2. B) nondisjunction at meiosis II in the mother
3. C) nondisjunction at meiosis I in the father
4. D) nondisjunction at meiosis II in the father
5. E) All of the choices could give rise to a Klinefelter male.

 

Answer:  D

Section:  04.02

Topic:  Sex Chromosomes and Sex Determination

Learning Objective:  04.02.01 Predict the sex of humans with different complements of X and Y chromosomes.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

51) In humans, XO individuals are females with Turner syndrome and XXY individuals are males with Klinefelter syndrome. Red-green color blindness is caused by an X-linked recessive allele. Suppose a color-blind man and a woman with normal vision and no family history of color blindness married and had a daughter who was color blind and had Turner syndrome. Which event could have given rise to this offspring?

1. A) nondisjunction at meiosis I in the mother
2. B) nondisjunction at meiosis II in the mother
3. C) nondisjunction at meiosis I in the father
4. D) nondisjunction at meiosis II in the father
5. E) nondisjunction at either meiosis I or meiosis II in the mother

 

Answer:  E

Section:  04.06; 04.07

Topic:  Validation of the Chromosome Theory; Sex-Linked and Sexually Dimorphic Traits in Humans

Learning Objective:  04.06.03 Predict phenotypes associated with nondisjunction of sex chromosomes.; 04.07.01 Determine from pedigree analysis whether human traits are X-linked or autosomal.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

 

52) Individuals with an XXY karyotype are ________ in humans and ________ in fruit flies.

1. A) male; male
2. B) male; female
3. C) female; male
4. D) female; female
5. E) male; intersexual

 

Answer:  B

Section:  04.02

Topic:  Sex Chromosomes and Sex Determination

Learning Objective:  04.02.03 Compare the means of sex determination in different organisms.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

53) In animal gametogenesis, a single primary spermatocyte generates ________ sperm, while a single primary oocyte generates ________ egg(s).

1. A) 1; 4
2. B) 1; 1
3. C) 4; 2
4. D) 4; 1
5. E) 4; 4

 

Answer:  D

Section:  04.05

Topic:  Gametogenesis

Learning Objective:  04.05.01 Compare the processes of oogenesis and spermatogenesis in humans.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

54) In which of the following cases will a Barr body be seen?

1. A) only XX
2. B) XY
3. C) XO
4. D) only XXY
5. E) both XX and XXY

 

Answer:  E

Section:  04.07

Topic:  Sex-Linked and Sexually Dimorphic Traits in Humans

Learning Objective:  04.07.02 Explain how human cells compensate for the X-linked gene dosage difference in XX and XY nuclei.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

 

 

55) You examine cells with a microscope and detect two Barr bodies in each cell. What is the most likely genotype of the cells?

1. A) XX
2. B) XY
3. C) XO
4. D) XXY
5. E) XXX

 

Answer:  E

Section:  04.07

Topic:  Sex-Linked and Sexually Dimorphic Traits in Humans

Learning Objective:  04.07.02 Explain how human cells compensate for the X-linked gene dosage difference in XX and XY nuclei.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

56) You engineer an XY mouse in which the SRY gene is inactivated. What do you expect to observe in this mouse?

1. A) The mouse will develop male anatomic features.
2. B) The mouse will develop female anatomic features.
3. C) The mouse’s Y chromosome will convert into an X chromosome.
4. D) The mouse’s X chromosome will convert into a Y chromosome.
5. E) The mouse will exhibit both male and female morphological features.

 

Answer:  B

Section:  04.02

Topic:  Sex Chromosomes and Sex Determination

Learning Objective:  04.02.02 Describe the basis of sex reversal in humans.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

57) An XY individual with a loss-of-function mutation in the SRY gene is expected to be female.

 

Answer:  TRUE

Section:  04.02

Topic:  Sex Chromosomes and Sex Determination

Learning Objective:  04.02.02 Describe the basis of sex reversal in humans.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

 

 

58) In human oogenesis, how many chromosomes does a primary oocyte carry?

1. A) 22
2. B) 23
3. C) 44
4. D) 46
5. E) 92

 

Answer:  D

Section:  04.05

Topic:  Gametogenesis

Learning Objective:  04.05.02 Distinguish between the sex chromosome complements of human female and male germ-line cells at different stages of gametogenesis.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

59) In human oogenesis, how many chromosomes does an oogonium carry?

1. A) 22
2. B) 23
3. C) 44
4. D) 46
5. E) 92

 

Answer:  D

Section:  04.05

Topic:  Gametogenesis

Learning Objective:  04.05.02 Distinguish between the sex chromosome complements of human female and male germ-line cells at different stages of gametogenesis.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

60) In human oogenesis, how many chromosomes does a secondary oocyte carry?

1. A) 22
2. B) 23
3. C) 44
4. D) 46
5. E) 92

 

Answer:  B

Section:  04.05

Topic:  Gametogenesis

Learning Objective:  04.05.02 Distinguish between the sex chromosome complements of human female and male germ-line cells at different stages of gametogenesis.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

 

 

61) In human oogenesis, how many chromosomes does an ovum carry?

1. A) 22
2. B) 23
3. C) 44
4. D) 46
5. E) 92

 

Answer:  B

Section:  04.05

Topic:  Gametogenesis

Learning Objective:  04.05.02 Distinguish between the sex chromosome complements of human female and male germ-line cells at different stages of gametogenesis.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

62) Suppose you discovered a new mutation in mice that causes a curved spine. You noticed that this mutant phenotype is present only in females. When curved-spine females are crossed with normal males, the progeny are always recovered in a 1:1:1 ratio of curved-spine females, normal females, and normal males. Explain the genetic basis for this ratio.

1. A) hemizygous or homozygous lethal autosomal allele
2. B) hemizygous or homozygous lethal sex-linked allele
3. C) recessive sex-linked allele
4. D) recessive autosomal allele
5. E) dominant sex-linked allele

 

Answer:  B

Explanation:  The gene is X-linked; the curved-spine allele is dominant to the normal allele in heterozygotes but is lethal in hemizygous males.

Section:  04.06

Topic:  Validation of the Chromosome Theory

Learning Objective:  04.06.02 Infer from the results of crosses whether or not a trait is sex-linked.

Bloom’s:  4. Analyze

Accessibility:  Keyboard Navigation

 

 

63) Which of the following statements is FALSE?

1. A) Sister chromatids of the same chromosome are identical.
2. B) Sister chromatids can be nonhomologous chromosomes.
3. C) Homologous chromosomes are not necessarily identical.
4. D) An example of a nonhomologous chromosome pair is paternal chromosome 1 and paternal chromosome 2 in a human.

 

Answer:  B

Section:  04.01

Topic:  Chromosomes – The Carriers of Genes

Learning Objective:  04.01.03 List the differences between sister chromatids and nonsister chromatids.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

64) At which phase of the cell cycle are sister chromatids generated?

1. A) G0
2. B) G1
3. C) G2
4. D) S
5. E) M

 

Answer:  D

Section:  04.01

Topic:  Chromosomes – The Carriers of Genes

Learning Objective:  04.01.03 List the differences between sister chromatids and nonsister chromatids.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

65) Individuals with Turner syndrome have which of the following sex chromosome complements?

1. A) XO
2. B) XX
3. C) XYY
4. D) XXY
5. E) XXX

 

Answer:  A

Section:  04.02

Topic:  Sex Chromosomes and Sex Determination

Learning Objective:  04.02.01 Predict the sex of humans with different complements of X and Y chromosomes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

66) Which term describes chromosomes whose centromeres are located closer to one end of the chromosome?

1. A) metacentric
2. B) acrocentric
3. C) holocentric
4. D) anacentric

 

Answer:  B

Section:  04.01

Topic:  Chromosomes – The Carriers of Genes

Learning Objective:  04.01.02 Distinguish between homologous and nonhomologous chromosomes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

67) Which of the following is a diploid cell destined for a specialized role in the production of gametes?

1. A) somatic cell
2. B) germ-line cell
3. C) spermatid
4. D) polar body
5. E) ootid

 

Answer:  B

Section:  04.01

Topic:  Chromosomes – The Carriers of Genes

Learning Objective:  04.01.01 Differentiate among somatic cells, gametes, and zygotes with regard to the number and origin of their chromosomes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

68) Structures that appear along the synaptonemal complex during pachytene where genetic material is exchanged between nonsister chromatids are the ________.

1. A) chiasmosomes
2. B) telomeres
3. C) centromeres
4. D) recombination nodules
5. E) kinetochores

 

Answer:  D

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.01 Describe the key chromosome behaviors during meiosis that lead to haploid gametes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

69) The domestic dog has 39 pairs of homologous chromosomes. A dog’s somatic cells have ________ chromosomes and gametes have ________ chromosomes.

1. A) 78; 78
2. B) 78; 39
3. C) 39; 15
4. D) 156; 78
5. E) 39; 39

 

Answer:  B

Section:  04.01

Topic:  Chromosomes – The Carriers of Genes

Learning Objective:  04.01.01 Differentiate among somatic cells, gametes, and zygotes with regard to the number and origin of their chromosomes.

Bloom’s:  3. Apply

Accessibility:  Keyboard Navigation

 

70) Cytokinesis in plant cells occurs by means of a cleavage furrow.

 

Answer:  FALSE

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.01 Describe the key chromosome behaviors during mitosis.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

71) DNA replication occurs in mitosis.

 

Answer:  TRUE

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.01 Describe the key chromosome behaviors during mitosis.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

72) Mitosis and cytoplasmic division result in the formation of two genetically identical cells.

 

Answer:  TRUE

Section:  04.03

Topic:  Mitosis – Cell Division That Preserves Chromosome Number

Learning Objective:  04.03.01 Describe the key chromosome behaviors during mitosis.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

 

 

73) Germ-line cells are haploid but gametes are diploid.

 

Answer:  FALSE

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.01 Describe the key chromosome behaviors during meiosis that lead to haploid gametes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

74) At the end of meiosis I, each daughter cell contains the sister chromatids from only one chromosome from each chromosomal pair.

 

Answer:  TRUE

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.01 Describe the key chromosome behaviors during meiosis that lead to haploid gametes.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

75) The period between meiosis I and II is termed interkinesis.

 

Answer:  TRUE

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.01 Describe the key chromosome behaviors during meiosis that lead to haploid gametes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

76) Crossing-over occurs during prophase I of meiosis.

 

Answer:  TRUE

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.03 Explain how the independent alignment of homologs, and also crossing-over during the first meiotic division, each contribute to the genetic diversity of gametes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

 

 

77) Crossing-over allows the reassortment of linked genes.

 

Answer:  TRUE

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.03 Explain how the independent alignment of homologs, and also crossing-over during the first meiotic division, each contribute to the genetic diversity of gametes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

78) The region where the homologous chromosomal pairs align is the metaphase plate.

 

Answer:  TRUE

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.03 Explain how the independent alignment of homologs, and also crossing-over during the first meiotic division, each contribute to the genetic diversity of gametes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

79) Orientation of each chromosomal pair on the spindle axis is random.

 

Answer:  TRUE

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.03 Explain how the independent alignment of homologs, and also crossing-over during the first meiotic division, each contribute to the genetic diversity of gametes.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

 

80) Crossing-over occurs in meiosis I and meiosis II.

 

Answer:  FALSE

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.03 Explain how the independent alignment of homologs, and also crossing-over during the first meiotic division, each contribute to the genetic diversity of gametes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

 

 

81) Chromosome duplication occurs between meiosis I and meiosis II.

 

Answer:  FALSE

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.01 Describe the key chromosome behaviors during meiosis that lead to haploid gametes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

82) In animal cells, cell division is accomplished by the formation of a cleavage furrow.

 

Answer:  TRUE

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.01 Describe the key chromosome behaviors during meiosis that lead to haploid gametes.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation

 

83) Daughter cells produced in meiosis are identical.

 

Answer:  FALSE

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.01 Describe the key chromosome behaviors during meiosis that lead to haploid gametes.

Bloom’s:  2. Understand

Accessibility:  Keyboard Navigation

84) Chromosome duplication occurs prior to both mitosis and meiosis.

 

Answer:  TRUE

Section:  04.04

Topic:  Meiosis – Cell Divisions That Halve Chromosome Number

Learning Objective:  04.04.02 Compare chromosome behaviors during mitosis and meiosis.

Bloom’s:  1. Remember

Accessibility:  Keyboard Navigation